【SEOテキスト】宇田雄一「古典物理学」【1d8b2】∃z∈R;z=r(t)-Qm(2,1)/E and
t=2nt0-1/α√αz2+2βz+c+β/α√-αcos-1(αz+β/√β2-αc)and θ(t)=2nθ0-h/√-α'cos-1(-α'/r(t)-β'/√β'2-α'A)【1d8b3】∃z∈R;z=r(t)-Qm(2,1)/E
and t=2nt0+1/α√αz2+2βz+c-β/α√-αcos-1(αz+β/√β2-αc)and θ(t)=2nθ0+h/√-α'cos-1(-α'/r(t)-β'/√β'2-α'A)【1d9】とは【1d9a】and【1d9b】のことだ。【1d9a】Qm(2,1)=-Z0+am(1,1)【1d9b】∀t∈R;[t≦0⇒【1d9b1】]and[t≧0⇒【1d9b2】]【1d9b1】∃z∈R;z=r(t)-Qm(2,1)/E
and t=-1/3β2(βz-c)√2βz+c and θ(t)=-h/√-α'cos-1(-α'/β'r(t)-1)【1d9b2】∃z∈R;z=r(t)-Qm(2,1)/E
and t=1/3β2(βz-c)√2βz+c and θ(t)=h/√-α'cos-1(-α'/β'r(t)-1)
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