【SEOテキスト】宇田雄一「古典物理学」【1d4b1】t0=√α'/-αE+β/-α√-αcos-1(-αβ'/A/√β2-αc)and
θ0(0)=0【1d4b2】∃z∈R;z=r(t)-Qm(2,1)/E and t=2nt0+1/α√αz2+2βz+c+β/α√-αcos-1(-αz-β/√β2-αc)and
θ(t)=θ0(n)-h/√α'cosh-1(α'/r(t)+β'/√β'2-α'A)【1d4b3】∃z∈R;z=r(t)-Qm(2,1)/E
and t=2nt0-1/α√αz2+2βz+c-β/α√-αcos-1(-αz-β/√β2-αc)and θ(t)=θ0(n)+h/√α'cosh-1(α'/r(t)+β'/√β'2-α'A)【1d5】とは【1d5a】and【1d5b】のことだ。【1d5a】Qm(2,1)=-abZ0【1d5b】∃t0∈R;∃θ0∈R(Z);【1d5b1】and[∀t∈R;∀n∈Z;-t0≦t-2nt0≦0⇒【1d5b2】]and[∀t∈R;∀n∈Z;0≦t-2nt0≦t0⇒【1d5b3】]【1d5b1】t0=πβ/-α√-α
and θ0(0)=0【1d5b2】∃z∈R;z=r(t)-Qm(2,1)/E and t=2nt0+1/α√αz2+2βz+c+β/α√-αcos-1(-αz-β/√β2-αc)and
θ(t)=θ0(n)-h/β'√2β'/r(t)+A【1d5b3】∃z∈R;z=r(t)-Qm(2,1)/E and t=2nt0-1/α√αz2+2βz+c-β/α√-αcos-1(-αz-β/√β2-αc)and
θ(t)=θ0(n)+h/β'√2β'/r(t)+A
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