【SEOテキスト】宇田雄一「古典物理学」V14の定義:V14∈F24(F14)and[V14(F3)=1]and∀n∈N;∀f∈F14,n;【1】and【2】【1】[V14(f)](N22)=V12(f(N12,n))【2】[V14(f)](N3)=f(N3),V3の定義:V3∈F03(F3)and∀f∈F3;【1】and【2】and【3】【1】∀i,j∈3;[V3(f)](i,j)=3∑k=1
ε(i,j,k)f(k,2)【2】∀i∈3;[V3(f)](4,i)=-[V3(f)](i,4)=f(i,1)【3】[V3(f)](4,4)=0,V1とV2,nとV4,nは、いずれも上へのではないが一対一だ。V12とV14は一対一でもなければ上へのでもない。V3は一対一上へのだ。V1の定義:∀A1∈N01(N01);V1(A1)∈F1(F1)and∀f∈F1;∀t,t'∈R({4});∀ξ∈N01;【1】⇒【2】【1】t'(4)=[A1(ξ)](4)and
t(4)=ξ(4)and ξ(3)=f(t,□)【2】∀k∈3;[[V1(A1)](f)](t',k)=[A1(ξ)](k),V2,nの定義:∀A1∈N01(N01);∀n∈N;∀p∈Pn;V2,n(A1,p)∈F2,n(F2,n)and∀f∈F2,n;∀(t,j,k)∈N2,n;[[V2,n(A1,p)](f)](t,j,p(k))=[[V1(A1)](f(□,□,k))](t,j),V3の定義:∀A1∈N01(N01);∀A2∈F3(F3);V3(A1,A2)∈F3(F3)and∀f∈F3;∀ξ∈N01;[[V3(A1,A2)](f)](A1(ξ),□,□)=A2(f(ξ,□,□)),V4,nの定義:∀A1∈N01(N01);∀A2∈F3(F3);∀n∈N;∀p∈Pn;V4,n(A1,A2,p)∈F4,n(F4,n)and∀f∈F4,n;【1】and【2】【1】[[V4,n(A1,A2,p)](f)](N2,n)=[V2,n(A1,p)](f(N2,n))【2】[[V4,n(A1,A2,p)](f)](N3)=[V3(A1,A2)](f(N3))
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