【SEOテキスト】宇田雄一「古典物理学」【2d】limε→+0ε2∫πθ=0∫2πφ=0[[sin(θ)]2cos(φ)f(c1(ξ,θ,φ,ε),3,1)-[sin(θ)]2sin(φ)f(c1(ξ,θ,φ,ε),2,1)+sin(θ)cos(θ)f(c1(ξ,θ,φ,ε),1,2)]=0【2e】limε→+0ε2∫πθ=0∫2πφ=0[[sin(θ)]2cos(φ)f(c2(ξ,θ,φ,ε),1,1)-[sin(θ)]2sin(φ)f(c2(ξ,θ,φ,ε),3,1)+sin(θ)cos(θ)f(c2(ξ,θ,φ,ε),2,2)]=0【2f】limε→+0ε2∫πθ=0∫2πφ=0[[sin(θ)]2cos(φ)f(c3(ξ,θ,φ,ε),2,1)-[sin(θ)]2sin(φ)f(c3(ξ,θ,φ,ε),1,1)+sin(θ)cos(θ)f(c3(ξ,θ,φ,ε),3,2)]=0【2g】limε→+0ε2∫πθ=0∫2πφ=0[[sin(θ)]2cos(φ)f(c4(ξ,θ,φ,ε),1,1)-[sin(θ)]2sin(φ)f(c4(ξ,θ,φ,ε),2,1)+sin(θ)cos(θ)f(c4(ξ,θ,φ,ε),3,1)]=∑k∈Nq(k)【2h】limε→+0ε2∫πθ=0∫2πφ=0[[sin(θ)]2cos(φ)f(c4(ξ,θ,φ,ε),1,2)-[sin(θ)]2sin(φ)f(c4(ξ,θ,φ,ε),2,2)+sin(θ)cos(θ)f(c4(ξ,θ,φ,ε),3,2)]=0ただし、c1(ξ,θ,φ,ε)∈R(4),[c1(ξ,θ,φ,ε)](1)=ξ(1),[c1(ξ,θ,φ,ε)](2)=ξ(2)+εsin(θ)cos(φ),[c1(ξ,θ,φ,ε)](3)=ξ(3)+εsin(θ)sin(φ),[c1(ξ,θ,φ,ε)](4)=ξ(4)+εcos(θ)
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